{"id":7414,"date":"2025-01-30T11:30:05","date_gmt":"2025-01-30T02:30:05","guid":{"rendered":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/?p=7414"},"modified":"2025-06-07T10:22:19","modified_gmt":"2025-06-07T01:22:19","slug":"%e9%ab%98%e3%81%95-h-%e3%81%8b%e3%82%89%e3%81%ae%e6%96%9c%e6%96%b9%e6%8a%95%e5%b0%84%e3%81%ae%e6%9c%80%e5%a4%a7%e6%b0%b4%e5%b9%b3%e5%88%b0%e9%81%94%e8%b7%9d%e9%9b%a2%e3%82%92%e6%b1%82%e3%82%81","status":"publish","type":"post","link":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/7414\/","title":{"rendered":"\u9ad8\u3055 h \u304b\u3089\u306e\u659c\u65b9\u6295\u5c04\u306e\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3092\u89e3\u6790\u7684\u306b\u6c42\u3081\u308b"},"content":{"rendered":"<p>\u300c<a href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e3%82%b3%e3%83%b3%e3%83%94%e3%83%a5%e3%83%bc%e3%82%bf%e6%bc%94%e7%bf%92\/%e9%ab%98%e3%81%95-h-%e3%81%8b%e3%82%89%e3%81%ae%e6%96%9c%e6%96%b9%e6%8a%95%e5%b0%84%e3%81%ae%e6%9c%80%e5%a4%a7%e5%88%b0%e9%81%94%e8%b7%9d%e9%9b%a2%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b%e6%ba%96\/\">\u9ad8\u3055 h \u304b\u3089\u306e\u659c\u65b9\u6295\u5c04\u306e\u6700\u5927\u5230\u9054\u8ddd\u96e2\u3092\u6c42\u3081\u308b\u6e96\u5099<\/a>\u300d\u306e\u30da\u30fc\u30b8\u3092\u53c2\u7167\u3002<\/p>\n<p>\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b\u6253\u3061\u51fa\u3057\u89d2\u5ea6 $\\theta$ \u3092\u6c42\u3081\u308b\u306b\u306f\uff0c\u5e73\u65b9\u6839\u3092\u542b\u3080\u975e\u7dda\u5f62\u65b9\u7a0b\u5f0f\u3092\u89e3\u304f\u5fc5\u8981\u304c\u3042\u308b\u306e\u3067\uff0cSymPy \u3067\u3084\u3063\u3066\u307f\u305f\u3002<\/p>\n<p><!--more--><\/p>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h3 id=\"\u30e9\u30a4\u30d6\u30e9\u30ea\u306e-import\">\u30e9\u30a4\u30d6\u30e9\u30ea\u306e import<\/h3>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[1]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"c1\"># 1\u6587\u5b57\u5909\u6570\u306e Symbol \u306e\u5ba3\u8a00\u304c\u7701\u7565\u3067\u304d\u308b<\/span>\r\n<span class=\"kn\">from<\/span> <span class=\"nn\">sympy.abc<\/span> <span class=\"kn\">import<\/span> <span class=\"o\">*<\/span>\r\n\r\n<span class=\"kn\">from<\/span> <span class=\"nn\">sympy<\/span> <span class=\"kn\">import<\/span> <span class=\"o\">*<\/span>\r\n\r\n<span class=\"n\">init_printing<\/span><span class=\"p\">()<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h3 id=\"\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b-$\\sin\\theta_{\\rm-m}$-\u3092\u89e3\u6790\u7684\u306b\u6c42\u3081\u308b\">\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b $\\sin\\theta_{\\rm max}$ \u3092\u89e3\u6790\u7684\u306b\u6c42\u3081\u308b<\/h3>\n<h4 id=\"\u6c34\u5e73\u5230\u9054\u8ddd\u96e2-$L$-\u3092-$s-\\equiv-\\sin-\\theta$-\u3067\u8868\u3059\">\u6c34\u5e73\u5230\u9054\u8ddd\u96e2 $L$ \u3092 $s \\equiv \\sin \\theta$ \u3067\u8868\u3059<\/h4>\n<p>\u6c34\u5e73\u5230\u9054\u8ddd\u96e2 $L(\\theta)$ \u3092 $s \\equiv \\sin \\theta$ \u3092\u4f7f\u3063\u3066\u8868\u3057\u3066\u307f\u307e\u3059\u3002<\/p>\n<p>\\begin{eqnarray}<br \/>\nL(\\theta) &amp;=&amp; \\left( \\sin{\\left(\\theta \\right)} + \\sqrt{2 H + \\sin^{2}{\\left(\\theta \\right)}}\\right) \\cos{\\left(\\theta \\right)} \\\\<br \/>\n&amp;=&amp; \\left(s + \\sqrt{s^2 + 2H}\\right) \\, \\sqrt{1 -s^2}<br \/>\n\\end{eqnarray}<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[2]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">var<\/span><span class=\"p\">(<\/span><span class=\"s1\">'H s'<\/span><span class=\"p\">,<\/span> <span class=\"n\">positive<\/span> <span class=\"o\">=<\/span> <span class=\"kc\">True<\/span><span class=\"p\">)<\/span> <span class=\"c1\"># H, s &gt; 0<\/span>\r\n\r\n<span class=\"k\">def<\/span> <span class=\"nf\">Ls<\/span><span class=\"p\">(<\/span><span class=\"n\">s<\/span><span class=\"p\">):<\/span>\r\n    <span class=\"k\">return<\/span> <span class=\"p\">(<\/span><span class=\"n\">s<\/span> <span class=\"o\">+<\/span> <span class=\"n\">sqrt<\/span><span class=\"p\">(<\/span><span class=\"mi\">2<\/span><span class=\"o\">*<\/span><span class=\"n\">H<\/span> <span class=\"o\">+<\/span> <span class=\"n\">s<\/span><span class=\"o\">**<\/span><span class=\"mi\">2<\/span><span class=\"p\">))<\/span> <span class=\"o\">*<\/span> <span class=\"n\">sqrt<\/span><span class=\"p\">(<\/span><span class=\"mi\">1<\/span> <span class=\"o\">-<\/span> <span class=\"n\">s<\/span><span class=\"o\">**<\/span><span class=\"mi\">2<\/span><span class=\"p\">)<\/span>\r\n<span class=\"n\">Ls<\/span><span class=\"p\">(<\/span><span class=\"n\">s<\/span><span class=\"p\">)<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[2]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\sqrt{1 -s^{2}} \\left(s + \\sqrt{2 H + s^{2}}\\right)$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h4 id=\"$L$-\u304c\u6700\u5927\u3068\u306a\u308b-$\\sin\\theta$-\u3092\u6c42\u3081\u308b\">$L$ \u304c\u6700\u5927\u3068\u306a\u308b $\\sin\\theta$ \u3092\u6c42\u3081\u308b<\/h4>\n<p><code>dLs<\/code>$\\displaystyle \\equiv\\frac{d L(s)}{d s} = 0$ \u3068\u306a\u308b $s \\equiv s_{\\rm max}$ \u3092 <code>solve()<\/code> \u3067\u6c42\u3081\u307e\u3059\u3002<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[3]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">dLs<\/span> <span class=\"o\">=<\/span> <span class=\"n\">diff<\/span><span class=\"p\">(<\/span><span class=\"n\">Ls<\/span><span class=\"p\">(<\/span><span class=\"n\">s<\/span><span class=\"p\">),<\/span> <span class=\"n\">s<\/span><span class=\"p\">)<\/span>\r\n<span class=\"n\">dLs<\/span> <span class=\"o\">=<\/span> <span class=\"n\">dLs<\/span><span class=\"o\">.<\/span><span class=\"n\">simplify<\/span><span class=\"p\">()<\/span>\r\n<span class=\"n\">dLs<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[3]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\frac{\\left(s + \\sqrt{2 H + s^{2}}\\right) \\left(-s^{2} -s \\sqrt{2 H + s^{2}} + 1\\right)}{\\sqrt{1 -s^{2}} \\sqrt{2 H + s^{2}}}$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p><code>dLs = 0<\/code> \u3092 <code>s<\/code> \u306b\u3064\u3044\u3066\u89e3\u304f\u3002<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[4]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">solve<\/span><span class=\"p\">(<\/span><span class=\"n\">dLs<\/span><span class=\"p\">,<\/span> <span class=\"n\">s<\/span><span class=\"p\">)<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[4]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\left[ \\frac{\\sqrt{2}}{2 \\sqrt{H + 1}}\\right]$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p>\u3068\u3044\u3046\u3053\u3068\u3067\uff0c\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b $\\sin\\theta_{\\rm max}$ \u306f<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\sin\\theta_{\\rm max} &amp;=&amp; s_{\\rm max} = \\frac{1}{\\sqrt{2 (1 + H)}} \\\\<br \/>\n\\therefore\\ \\ \\theta_{\\rm max} &amp;=&amp; \\arcsin\\left(\\frac{1}{\\sqrt{2 (1 + H)}}\\right)<br \/>\n\\end{eqnarray}<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h4 id=\"\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\">\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2<\/h4>\n<p>\u305d\u306e\u3068\u304d\u306e\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2 $L_{\\rm max} = L(\\theta_{\\rm max}, H)$ \u306f&#8230;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[5]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">smax<\/span> <span class=\"o\">=<\/span> <span class=\"mi\">1<\/span><span class=\"o\">\/<\/span><span class=\"n\">sqrt<\/span><span class=\"p\">(<\/span><span class=\"mi\">2<\/span><span class=\"o\">*<\/span><span class=\"p\">(<\/span><span class=\"mi\">1<\/span><span class=\"o\">+<\/span><span class=\"n\">H<\/span><span class=\"p\">))<\/span>\r\n<span class=\"n\">Ls<\/span><span class=\"p\">(<\/span><span class=\"n\">smax<\/span><span class=\"p\">)<\/span><span class=\"o\">.<\/span><span class=\"n\">simplify<\/span><span class=\"p\">()<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[5]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\frac{\\sqrt{2 H + 1} \\left(\\sqrt{4 H \\left(H + 1\\right) + 1} + 1\\right)}{2 \\left(H + 1\\right)}$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p>\u7c21\u5358\u5316\u3057\u3066\u304f\u308c\u306a\u3044\u306a\u3041&#8230;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h3 id=\"\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b-$\\tan\\theta_{\\rm-m}$-\u3092\u89e3\u6790\u7684\u306b\u6c42\u3081\u308b\">\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b $\\tan\\theta_{\\rm max}$ \u3092\u89e3\u6790\u7684\u306b\u6c42\u3081\u308b<\/h3>\n<p>\u6c34\u5e73\u5230\u9054\u8ddd\u96e2 $L(\\theta)$ \u3092 $t \\equiv \\tan \\theta$ \u3092\u4f7f\u3063\u3066\u8868\u3057\u3066\u307f\u307e\u3059\u3002<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h4 id=\"\u6c34\u5e73\u5230\u9054\u8ddd\u96e2-$L$-\u3092-$t-\\equiv-\\tan\\theta$-\u3067\u8868\u3059\">\u6c34\u5e73\u5230\u9054\u8ddd\u96e2 $L$ \u3092 $t \\equiv \\tan\\theta$ \u3067\u8868\u3059<\/h4>\n<p>$t \\equiv \\tan\\theta$ \u3068\u3057\u3066\u898f\u683c\u5316\u3055\u308c\u305f\u6c34\u5e73\u5230\u9054\u8ddd\u96e2 $L$ \u3092 $t$ \u3067\u8868\u3059\u3068<\/p>\n<p>\\begin{eqnarray}<br \/>\nL(t)<br \/>\n&amp;=&amp; \\frac{1}{1+t^2} \\left\\{t + \\sqrt{(1+2H)\\, t^2 + 2H} \\right\\}<br \/>\n\\end{eqnarray}<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[6]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">var<\/span><span class=\"p\">(<\/span><span class=\"s1\">'t H'<\/span><span class=\"p\">,<\/span> <span class=\"n\">positive<\/span> <span class=\"o\">=<\/span> <span class=\"kc\">True<\/span><span class=\"p\">)<\/span> <span class=\"c1\"># positive = True \u3068\u3059\u308b\u3068\u5409<\/span>\r\n\r\n<span class=\"k\">def<\/span> <span class=\"nf\">Lt<\/span><span class=\"p\">(<\/span><span class=\"n\">t<\/span><span class=\"p\">):<\/span>\r\n    <span class=\"k\">return<\/span> <span class=\"p\">(<\/span><span class=\"n\">t<\/span><span class=\"o\">+<\/span><span class=\"n\">sqrt<\/span><span class=\"p\">((<\/span><span class=\"mi\">1<\/span><span class=\"o\">+<\/span><span class=\"mi\">2<\/span><span class=\"o\">*<\/span><span class=\"n\">H<\/span><span class=\"p\">)<\/span><span class=\"o\">*<\/span><span class=\"n\">t<\/span><span class=\"o\">**<\/span><span class=\"mi\">2<\/span> <span class=\"o\">+<\/span> <span class=\"mi\">2<\/span><span class=\"o\">*<\/span><span class=\"n\">H<\/span><span class=\"p\">))<\/span><span class=\"o\">\/<\/span><span class=\"p\">(<\/span><span class=\"mi\">1<\/span> <span class=\"o\">+<\/span> <span class=\"n\">t<\/span><span class=\"o\">**<\/span><span class=\"mi\">2<\/span><span class=\"p\">)<\/span>\r\n<span class=\"n\">Lt<\/span><span class=\"p\">(<\/span><span class=\"n\">t<\/span><span class=\"p\">)<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[6]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\frac{t + \\sqrt{2 H + t^{2} \\left(2 H + 1\\right)}}{t^{2} + 1}$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h4 id=\"$L$-\u304c\u6700\u5927\u3068\u306a\u308b-$\\tan\\theta$-\u3092\u6c42\u3081\u308b\">$L$ \u304c\u6700\u5927\u3068\u306a\u308b $\\tan\\theta$ \u3092\u6c42\u3081\u308b<\/h4>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p>$\\displaystyle \\frac{d L(t)}{dt} = 0$ \u3068\u306a\u308b $t \\equiv t_{\\rm max}$ \u3092 <code>solve()<\/code> \u3067\u6c42\u3081\u307e\u3059\u3002<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[7]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">dLt<\/span> <span class=\"o\">=<\/span> <span class=\"n\">diff<\/span><span class=\"p\">(<\/span><span class=\"n\">Lt<\/span><span class=\"p\">(<\/span><span class=\"n\">t<\/span><span class=\"p\">),<\/span> <span class=\"n\">t<\/span><span class=\"p\">)<\/span>\r\n<span class=\"n\">sols<\/span> <span class=\"o\">=<\/span> <span class=\"n\">solve<\/span><span class=\"p\">(<\/span><span class=\"n\">dLt<\/span><span class=\"p\">,<\/span> <span class=\"n\">t<\/span><span class=\"p\">)<\/span>\r\n<span class=\"n\">sols<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[7]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\left[ \\frac{1}{\\sqrt{2 H + 1}}\\right]$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p>\u5ff5\u306e\u305f\u3081\uff0c\u672c\u5f53\u306b\u89e3\u306b\u306a\u3063\u3066\u3044\u308b\u304b\uff0c\u78ba\u8a8d\u3057\u307e\u3059\u3002<\/p>\n<p><code>dLt.subs(t, sols[0])<\/code> \u3068\u3057\u3066\uff0c<code>dLt<\/code> \u306e <code>t<\/code> \u306b <code>sols[0]<\/code> \u3092\u4ee3\u5165\u3057\uff0c<code>simplify()<\/code> \u3067\u7c21\u5358\u5316\u3057\u3066\u307f\u307e\u3059\u3002<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[8]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">simplify<\/span><span class=\"p\">(<\/span><span class=\"n\">dLt<\/span><span class=\"o\">.<\/span><span class=\"n\">subs<\/span><span class=\"p\">(<\/span><span class=\"n\">t<\/span><span class=\"p\">,<\/span> <span class=\"n\">sols<\/span><span class=\"p\">[<\/span><span class=\"mi\">0<\/span><span class=\"p\">]))<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[8]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle 0$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p>\u3088\u3063\u3066\uff0c$L(t)$ \u304c\u6700\u5927\u3068\u306a\u308b $t$ \u306e\u5024 $t_{\\rm max}$ \u306f&#8230;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[9]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">tmax<\/span> <span class=\"o\">=<\/span>  <span class=\"mi\">1<\/span><span class=\"o\">\/<\/span><span class=\"n\">sqrt<\/span><span class=\"p\">(<\/span><span class=\"mi\">1<\/span> <span class=\"o\">+<\/span> <span class=\"mi\">2<\/span><span class=\"o\">*<\/span><span class=\"n\">H<\/span><span class=\"p\">)<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h4 id=\"\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2-$L_{\\rm-max}$\">\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2<\/h4>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[10]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">simplify<\/span><span class=\"p\">(<\/span><span class=\"n\">Lt<\/span><span class=\"p\">(<\/span><span class=\"n\">tmax<\/span><span class=\"p\">))<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[10]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\sqrt{2 H + 1}$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<p>\u3064\u307e\u308a\uff0c\u9ad8\u3055 $H$ \u306e\u3068\u304d\u306e\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u306f\uff0c<\/p>\n<p>$$L_{\\rm max} = \\sqrt{1 + 2H}$$<\/p>\n<p>\u3068\u306a\u308b\u3053\u3068\u304c\u308f\u304b\u308a\u307e\u3059\u3002<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">\n<h4 id=\"\u3053\u306e\u3068\u304d\u306e\u6ede\u7a7a\u6642\u9593-$T_1(\\theta)$-\u306f...\">\u3053\u306e\u3068\u304d\u306e\u6ede\u7a7a\u6642\u9593 $T_1(\\theta)$ \u306f&#8230;<\/h4>\n<p>$$T_1(\\theta) = \\sin\\theta + \\sqrt{\\sin^2\\theta + 2 H}$$<\/p>\n<p>\u306b<\/p>\n<p>\\begin{eqnarray}<br \/>\nt_{\\rm max} &amp;=&amp; \\tan\\theta_{\\rm max} = \\frac{1}{\\sqrt{1 + 2 H}} \\\\<br \/>\n\\therefore\\ \\ \\theta_{\\rm max} &amp;=&amp; \\arctan \\left(\\frac{1}{\\sqrt{1 + 2 H}}\\right)<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3067\u6c7a\u307e\u308b $\\theta_{\\rm max}$ \u3092\u4ee3\u5165\u3057\u3066&#8230;<\/p>\n<p>\u3042\u308b\u3044\u306f\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\ns_{\\rm max} &amp;=&amp; \\sin\\theta_{\\rm max} = \\frac{1}{\\sqrt{2(1 + H)}}<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3092\u4f7f\u3063\u3066&#8230;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing code_cell rendered\">\n<div class=\"input\">\n<div class=\"prompt input_prompt\">In\u00a0[11]:<\/div>\n<div class=\"inner_cell\">\n<div class=\"input_area\">\n<div class=\" highlight hl-ipython3\">\n<pre><span class=\"n\">T1<\/span> <span class=\"o\">=<\/span> <span class=\"n\">smax<\/span> <span class=\"o\">+<\/span> <span class=\"n\">sqrt<\/span><span class=\"p\">(<\/span><span class=\"n\">factor<\/span><span class=\"p\">(<\/span><span class=\"n\">smax<\/span><span class=\"o\">**<\/span><span class=\"mi\">2<\/span> <span class=\"o\">+<\/span> <span class=\"mi\">2<\/span><span class=\"o\">*<\/span><span class=\"n\">H<\/span><span class=\"p\">))<\/span>\r\n<span class=\"n\">T1<\/span><span class=\"o\">.<\/span><span class=\"n\">factor<\/span><span class=\"p\">()<\/span>\r\n<\/pre>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"output_wrapper\">\n<div class=\"output\">\n<div class=\"output_area\">\n<div class=\"prompt output_prompt\">Out[11]:<\/div>\n<div class=\"output_latex output_subarea output_execute_result\">$\\displaystyle \\sqrt{2} \\sqrt{H + 1}$<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"cell border-box-sizing text_cell rendered\">\n<div class=\"prompt input_prompt\"><\/div>\n<div class=\"inner_cell\">\n<div class=\"text_cell_render border-box-sizing rendered_html\">$$T_1 = \\sin\\theta_{\\rm max} + \\sqrt{\\sin^2\\theta_{\\rm max} + 2H} = \\sqrt{2 (1 + H)}$$<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>\u300c\u9ad8\u3055 h \u304b\u3089\u306e\u659c\u65b9\u6295\u5c04\u306e\u6700\u5927\u5230\u9054\u8ddd\u96e2\u3092\u6c42\u3081\u308b\u6e96\u5099\u300d\u306e\u30da\u30fc\u30b8\u3092\u53c2\u7167\u3002<\/p>\n<p>\u6700\u5927\u6c34\u5e73\u5230\u9054\u8ddd\u96e2\u3068\u306a\u308b\u6253\u3061\u51fa\u3057\u89d2\u5ea6 $\\theta$ \u3092\u6c42\u3081\u308b\u306b\u306f\uff0c\u5e73\u65b9\u6839\u3092\u542b\u3080\u975e\u7dda\u5f62\u65b9\u7a0b\u5f0f\u3092\u89e3\u304f\u5fc5\u8981\u304c\u3042\u308b\u306e\u3067\uff0cSymPy \u3067\u3084\u3063\u3066\u307f\u305f\u3002<\/p><p><a class=\"more-link btn\" href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/7414\/\">\u7d9a\u304d\u3092\u8aad\u3080<\/a><\/p>\n","protected":false},"author":33,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"inline_featured_image":false,"footnotes":""},"categories":[12,25],"tags":[],"class_list":["post-7414","post","type-post","status-publish","format-standard","hentry","category-sympy","category-25","nodate","item-wrap"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts\/7414","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/users\/33"}],"replies":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/comments?post=7414"}],"version-history":[{"count":19,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts\/7414\/revisions"}],"predecessor-version":[{"id":10176,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts\/7414\/revisions\/10176"}],"wp:attachment":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/media?parent=7414"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/categories?post=7414"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/tags?post=7414"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}