{"id":4811,"date":"2023-01-05T13:24:50","date_gmt":"2023-01-05T04:24:50","guid":{"rendered":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/?p=4811"},"modified":"2023-03-14T16:47:36","modified_gmt":"2023-03-14T07:47:36","slug":"%e9%9d%99%e9%9b%bb%e5%a0%b4%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b%e9%9a%9b%e3%81%ab%e4%bd%bf%e3%81%a3%e3%81%9f%e7%a9%8d%e5%88%86%e3%82%92%e4%ba%ba%e5%8a%9b%e3%81%a7%e6%b1%82%e3%82%81%e3%81%a6%e3%81%bf-2","status":"publish","type":"post","link":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/4811\/","title":{"rendered":"\u9759\u96fb\u5834\u3092\u6c42\u3081\u308b\u969b\u306b\u4f7f\u3063\u305f\u7a4d\u5206\u3092\u4eba\u529b\u3067\u6c42\u3081\u3066\u307f\u308b\uff1a\u7b2c4\u8a71"},"content":{"rendered":"<p><a href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e9%9b%bb%e7%a3%81%e6%b0%97%e5%ad%a6-i\/%e9%9d%99%e9%9b%bb%e5%a0%b4%ef%bc%9a%e9%9b%bb%e8%8d%b7%e5%af%86%e5%ba%a6%e3%81%8b%e3%82%89%e7%9b%b4%e6%8e%a5%e9%9b%bb%e5%a0%b4%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b\/%e5%8f%82%e8%80%83%ef%bc%9a%e9%9d%99%e9%9b%bb%e5%a0%b4%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b%e9%9a%9b%e3%81%ab%e4%bd%bf%e3%81%a3%e3%81%9f%e7%a9%8d%e5%88%86%e3%82%92-maxima-jupyter-%e3%81%a7%e7%a2%ba\/\" target=\"_blank\" rel=\"noopener\">\u9759\u96fb\u5834\u3092\u6c42\u3081\u308b\u969b\u306b\u4f7f\u3063\u305f\u7a4d\u5206\u306f Maxima \u3092\u6570\u5b66\u516c\u5f0f\u96c6\u3068\u3057\u3066\u4f7f\u3046\u3053\u3068\u3067\u78ba\u8a8d\u3067\u304d\u3066\u3044\u308b<\/a>\u304c\uff0cMaxima \u3067\u89e3\u6790\u7684\u306b\u7a4d\u5206\u3067\u304d\u308b\u3053\u3068\u304c\u308f\u304b\u308c\u3070\uff0c\u4eba\u529b\u3067\u3082\u89e3\u3044\u3066\u307f\u305f\u304f\u306a\u308b\u3082\u306e\u3002\u305d\u306e\u30b7\u30ea\u30fc\u30ba\u7b2c4\u8a71\u306f\uff0c<a href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e9%9b%bb%e7%a3%81%e6%b0%97%e5%ad%a6-i\/%e9%9d%99%e9%9b%bb%e5%a0%b4%ef%bc%9a%e9%9b%bb%e8%8d%b7%e5%af%86%e5%ba%a6%e3%81%8b%e3%82%89%e7%9b%b4%e6%8e%a5%e9%9b%bb%e5%a0%b4%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b\/#i-9\">\u7403\u5bfe\u79f0\u306a\u96fb\u8377\u5206\u5e03\u306b\u3088\u308b\u96fb\u5834<\/a>\u3092\u6c42\u3081\u308b\u969b\u306b\u4f7f\u3063\u305f\u7a4d\u5206\u3002\u96fb\u78c1\u6c17\u5b66\u3068\u3044\u3046\u3088\u308a\u306f\u7406\u5de5\u7cfb\u306e\u6570\u5b66B\uff08\u5fae\u5206\u7a4d\u5206\uff09\u306e\u6f14\u7fd2\u554f\u984c\u7528\u306b\u3002<\/p>\n<p><!--more--><\/p>\n<h3><a href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e9%9b%bb%e7%a3%81%e6%b0%97%e5%ad%a6-i\/%e9%9d%99%e9%9b%bb%e5%a0%b4%ef%bc%9a%e9%9b%bb%e8%8d%b7%e5%af%86%e5%ba%a6%e3%81%8b%e3%82%89%e7%9b%b4%e6%8e%a5%e9%9b%bb%e5%a0%b4%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b\/#i-9\">\u7403\u5bfe\u79f0\u306a\u96fb\u8377\u5206\u5e03\u306b\u3088\u308b\u96fb\u5834<\/a>\u3067\u4f7f\u3063\u305f\u7a4d\u5206<\/h3>\n<h4>$\\boldsymbol{r} = (0, 0, r)$ \u306e\u5834\u5408<\/h4>\n<p>$$ \\int_0^{\\pi} \\sin\\theta&#8217; d\\theta&#8217;<br \/>\n\\frac{(r-r&#8217;\\cos\\theta&#8217;)}{\\left\\{r^2 + (r&#8217;)^2 -2 r r&#8217; \\cos\\theta&#8217;\\right\\}^{3\/2}}<br \/>\n= \\frac{2}{r^2} H(r-r&#8217;) = \\left\\{<br \/>\n\\begin{array}{ll}<br \/>\n{\\displaystyle \\frac{2}{r^2}} &amp; (r \\geq r&#8217;)\\\\ \\ \\\\<br \/>\n0 &amp; (r &lt; r&#8217;)<br \/>\n\\end{array}<br \/>\n\\right.$$<\/p>\n<p>\u306a\u305c\u3053\u306e\u7a4d\u5206\u306b\u30d8\u30d3\u30b5\u30a4\u30c9\u306e\u968e\u6bb5\u95a2\u6570 $H(r-r&#8217;)$ \u304c\u51fa\u3066\u304f\u308b\u306e\u304b\u3092\u5c11\u3057\u8003\u5bdf\u3002<\/p>\n<p>$t = \\cos\\theta&#8217;$ \u3068\u304a\u304f\u3068\uff0c$\\sin\\theta&#8217; \\,d\\theta&#8217; = &#8211; dt$<\/p>\n<p>\\begin{eqnarray}<br \/>\n&amp;&amp;\\int_0^{\\pi}<br \/>\n\\frac{(r-r&#8217;\\cos\\theta&#8217;)\\sin\\theta&#8217; d\\theta&#8217;}{\\left\\{r^2 + (r&#8217;)^2 -2 r r&#8217; \\cos\\theta&#8217;\\right\\}^{3\/2}} \\\\<br \/>\n&amp;=&amp; \\int_{-1}^1\u00a0 \\frac{(r-r&#8217; t)}{\\left\\{r^2 + (r&#8217;)^2 -2 r r&#8217; t\\right\\}^{3\/2}} dt \\\\<br \/>\n&amp;=&amp; \\frac{1}{r^2} \\Biggl[\\frac{r t &#8211; r&#8217;}{\\sqrt{r^2 + (r&#8217;)^2 &#8211; 2 r r&#8217; t}} \\Biggr]_{-1}^1 \\\\<br \/>\n&amp;=&amp; \\frac{1}{r^2} \\left( \\frac{r-r&#8217;}{\\sqrt{(r &#8211; r&#8217;)^2}} &#8211; \\frac{-r-r&#8217;}{\\sqrt{(r + r&#8217;)^2}}\\right) \\\\<br \/>\n&amp;=&amp; \\frac{1}{r^2} \\left( \\frac{r-r&#8217;}{|r &#8211; r&#8217;|} + \\frac{r +r&#8217;}{|r + r&#8217;|}\\right) \\\\<br \/>\n&amp;=&amp; \\frac{1}{r^2} \\left( 1 + \\frac{r-r&#8217;}{|r &#8211; r&#8217;|} \\right) \\\\<br \/>\n&amp;=&amp;\\left\\{<br \/>\n\\begin{array}{ll}<br \/>\n{\\displaystyle \\frac{2}{r^2}} &amp; (r \\geq r&#8217;)\\\\ \\ \\\\<br \/>\n0 &amp; (r &lt; r&#8217;)<br \/>\n\\end{array}<br \/>\n\\right.<br \/>\n\\end{eqnarray}<\/p>\n<h4>$\\boldsymbol{r} = (x, y, z)$ \u306e\u4e00\u822c\u306e\u5834\u5408<\/h4>\n<p>\u305d\u3082\u305d\u3082\u7403\u5bfe\u79f0\u306a\u96fb\u8377\u5bc6\u5ea6 $\\rho(r)$ \u306b\u3064\u3044\u3066<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{E} &amp;=&amp;<br \/>\n\\frac{1}{4\\pi\\varepsilon_0}\\iiint \\frac{\\rho(r&#8217;)(\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;)}{|\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;|^3} dV&#8217; \\\\<br \/>\n&amp;=&amp; \\frac{1}{4\\pi\\varepsilon_0} \\int (r&#8217;)^2 dr&#8217; \\rho(r&#8217;) \\iint \\sin\\theta&#8217;\u00a0 d\\theta&#8217; \\,d\\phi&#8217;<br \/>\n\\frac{\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;}{\\left(r^2 + (r&#8217;)^2 &#8211; 2\\boldsymbol{r}\\cdot\\boldsymbol{r}&#8217;\\right)^{\\frac{3}{2}} }<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3092\u6c42\u3081\u308b\u306e\u304c\u672c\u984c\u3067\u3042\u3063\u305f\u3002\u3053\u306e\u7a4d\u5206\u304c\u96e3\u3057\u305d\u3046\u3060\u304b\u3089\uff0c$\\boldsymbol{r} = (0, 0, r)$ \u306e\u5834\u5408\u306b\u3084\u3063\u3066\u307f\u305f\u308f\u3051\u3060\u3002\u4e00\u822c\u306e $\\boldsymbol{r} = (x, y, z)$ \u306e\u5834\u5408\u306f\uff0c\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u3057\u3066\u307f\u305f\u3089\u3069\u3046\u3060\u308d\u3046\u304b\u3002<\/p>\n<p>\u307e\u305a\uff0c<\/p>\n<p>$$\\boldsymbol{r}&#8217; = r&#8217;<br \/>\n\\sin\\theta&#8217; \\cos\\phi&#8217; \\boldsymbol{i}<br \/>\n+ r&#8217;\u00a0 \\sin\\theta&#8217; \\sin\\phi&#8217; \\boldsymbol{j} +r&#8217; \u00a0 \\cos\\theta&#8217; \\boldsymbol{k}<br \/>\n$$<\/p>\n<p>\u306e\u304b\u308f\u308a\u306b\uff0c$\\displaystyle \\boldsymbol{e}_r \\equiv \\frac{\\boldsymbol{r}}{r}$ \u3068\u3057\uff0c$\\boldsymbol{e}_r$ \u306b\u76f4\u4ea4\u3059\u308b\u57fa\u672c\u30d9\u30af\u30c8\u30eb $\\boldsymbol{e}_1, \\boldsymbol{e}_2$ \u3092\u6b21\u306e\u3088\u3046\u306b\u3057\u3066\u5c0e\u5165\u3059\u308b\u3002<\/p>\n<p>\u307e\u305a\uff0c\u6b63\u898f\u76f4\u4ea4\u95a2\u4fc2\u306f<\/p>\n<p>$$\\boldsymbol{e}_r \\cdot \\boldsymbol{e}_r = 1, \\ \\<br \/>\n\\boldsymbol{e}_1 \\cdot \\boldsymbol{e}_1= 1, \\ \\<br \/>\n\\boldsymbol{e}_2 \\cdot \\boldsymbol{e}_2 = 1$$<\/p>\n<p>$$\\boldsymbol{e}_r \\cdot \\boldsymbol{e}_1 = 0, \\ \\<br \/>\n\\boldsymbol{e}_r \\cdot \\boldsymbol{e}_2= 0, \\ \\<br \/>\n\\boldsymbol{e}_1 \\cdot \\boldsymbol{e}_2 = 0$$<\/p>\n<p>\u307e\u305f\uff0c\u5916\u7a4d\u306b\u3064\u3044\u3066\u306f<\/p>\n<p>$$\\boldsymbol{e}_r \\times \\boldsymbol{e}_1 = \\boldsymbol{e}_2, \\ \\<br \/>\n\\boldsymbol{e}_r \\times \\boldsymbol{e}_2= &#8211; \\boldsymbol{e}_1$$<\/p>\n<p>$\\boldsymbol{i} , \\boldsymbol{j} , \\boldsymbol{k} $ \u7cfb\u304b\u3089 $\\boldsymbol{e}_r,\u00a0 \\boldsymbol{e}_1, \\boldsymbol{e}_2$ \u7cfb\u3078\u306f\u539f\u70b9\u306e\u307e\u308f\u308a\u306e\u5ea7\u6a19\u7cfb\u306e\u56de\u8ee2\u306b\u3088\u3063\u3066\u5909\u63db\u3067\u304d\u308b\u3002<\/p>\n<p>\u4eca\u5f8c\uff0c\u8a08\u7b97\u306e\u969b\u306f $\\boldsymbol{e}_r,\u00a0 \\boldsymbol{e}_1, \\boldsymbol{e}_2$ \u7cfb\u3092\u4f7f\u3046\u3053\u3068\u306b\u3057\u3066\uff0c<\/p>\n<p>$$\\boldsymbol{r}&#8217; =<br \/>\nr&#8217;\u00a0 \\sin\\vartheta&#8217; \\cos\\varphi&#8217; \\boldsymbol{e}_1<br \/>\n+ r&#8217;\u00a0 \\sin\\vartheta&#8217; \\sin\\varphi&#8217; \\boldsymbol{e}_2 +r&#8217; \u00a0 \\cos\\vartheta&#8217; \\boldsymbol{e}_r<br \/>\n$$<\/p>\n<p>\u3059\u3050\u4f7f\u3046\u91cf\u3092\u3042\u3089\u304b\u3058\u3081\u8a08\u7b97\u3057\u3066\u304a\u304f\u3068\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{r}\\cdot\\boldsymbol{r}&#8217; &amp;=&amp; r r&#8217; \\cos\\vartheta&#8217; \\\\<br \/>\n\\boldsymbol{r}\\times\\boldsymbol{r}&#8217; &amp;=&amp; r r&#8217; \\left(<br \/>\n\\sin\\vartheta&#8217; \\cos\\varphi&#8217; \\boldsymbol{e}_r\\times\\boldsymbol{e}_1<br \/>\n+ \\sin\\vartheta&#8217; \\sin\\varphi&#8217; \\boldsymbol{e}_r\\times\\boldsymbol{e}_2\\right) \\\\<br \/>\n&amp;=&amp; r r&#8217; \\left(<br \/>\n\\sin\\vartheta&#8217; \\cos\\varphi&#8217; \\boldsymbol{e}_2<br \/>\n-\\sin\\vartheta&#8217; \\sin\\varphi&#8217; \\boldsymbol{e}_1\\right)<br \/>\n\\end{eqnarray}<\/p>\n<p>\u96fb\u5834\u3092\u6c42\u3081\u308b\u7a4d\u5206\u5f0f\u306f<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{E} &amp;=&amp;<br \/>\n\\frac{1}{4\\pi\\varepsilon_0}\\iiint \\frac{\\rho(r&#8217;)(\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;)}{|\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;|^3} dV&#8217; \\\\<br \/>\n&amp;=&amp; \\frac{1}{4\\pi\\varepsilon_0} \\int (r&#8217;)^2 dr&#8217; \\rho(r&#8217;) \\iint \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217; \\,d\\varphi&#8217;<br \/>\n\\frac{\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;}{\\left(r^2 + (r&#8217;)^2 &#8211; 2\\boldsymbol{r}\\cdot\\boldsymbol{r}&#8217;\\right)^{\\frac{3}{2}} }<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3053\u3053\u3067\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{F} &amp;\\equiv&amp;<br \/>\n\\iint \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217; \\,d\\varphi&#8217;<br \/>\n\\frac{\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;}{\\left(r^2 + (r&#8217;)^2 &#8211; 2\\boldsymbol{r}\\cdot\\boldsymbol{r}&#8217;\\right)^{\\frac{3}{2}} } \\\\<br \/>\n&amp;=&amp; \\iint \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217; \\,d\\varphi&#8217;<br \/>\n\\frac{\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;}{\\left(r^2 + (r&#8217;)^2 &#8211; 2r r&#8217; \\cos\\vartheta&#8217;\\right)^{\\frac{3}{2}} }<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3068\u5b9a\u7fa9\u3059\u308b\u3068\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{r} \\times\\boldsymbol{F}<br \/>\n&amp;=&amp; \\iint \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217; \\,d\\varphi&#8217;<br \/>\n\\frac{- \\boldsymbol{r}\\times\\boldsymbol{r}&#8217;}{\\left(r^2 + (r&#8217;)^2 &#8211; 2r r&#8217; \\cos\\vartheta&#8217;\\right)^{\\frac{3}{2}} } \\\\<br \/>\n&amp;=&amp;\\int \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217; {\\color{red}{\\int_0^{2\\pi}\\,d\\varphi&#8217;}}<br \/>\n\\frac{- r r&#8217; \\left(<br \/>\n\\sin\\vartheta&#8217; {\\color{red}{\\cos\\varphi&#8217;}} \\boldsymbol{e}_2<br \/>\n-\\sin\\vartheta&#8217; {\\color{red}{\\sin\\varphi&#8217;}} \\boldsymbol{e}_1\\right)}{\\left(r^2 + (r&#8217;)^2 &#8211; 2r r&#8217; \\cos\\vartheta&#8217;\\right)^{\\frac{3}{2}} } \\\\<br \/>\n&amp;=&amp; \\boldsymbol{0}<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3068\u306a\u308a\uff0c$\\boldsymbol{F}$ \u306f $\\boldsymbol{r}$ \u306b\u5e73\u884c\u306a\u6210\u5206\u3057\u304b\u3082\u305f\u306a\u3044\u3053\u3068\u304c\u7c21\u5358\u306b\u308f\u304b\u308b\u3002<\/p>\n<p>\u3057\u305f\u304c\u3063\u3066<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{F} &amp;=&amp; \\left(\\boldsymbol{e}_r\\cdot\\boldsymbol{F}\\right)\\, \\boldsymbol{e}_r \\\\<br \/>\n&amp;=&amp; \\frac{\\boldsymbol{r}}{r^2} \\left(\\boldsymbol{r}\\cdot\\boldsymbol{F}\\right) \\\\<br \/>\n&amp;=&amp; \\frac{\\boldsymbol{r}}{r^2} \\iint \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217; \\,d\\varphi&#8217;<br \/>\n\\frac{\\boldsymbol{r}\\cdot(\\boldsymbol{r} &#8211; \\boldsymbol{r}&#8217;)}{\\left(r^2 + (r&#8217;)^2 &#8211; 2r r&#8217; \\cos\\vartheta&#8217;\\right)^{\\frac{3}{2}} }\u00a0 \\\\<br \/>\n&amp;=&amp; \\frac{\\boldsymbol{r}}{r} \\int_0^{2\\pi} \\,d\\varphi&#8217; \\int_0^{\\pi} \\sin\\vartheta&#8217;\u00a0 d\\vartheta&#8217;<br \/>\n\\frac{r &#8211;\u00a0 r&#8217;\\cos\\vartheta&#8217;}{\\left(r^2 + (r&#8217;)^2 &#8211; 2r r&#8217; \\cos\\vartheta&#8217;\\right)^{\\frac{3}{2}} }\u00a0 \\\\<br \/>\n&amp;=&amp; 2\\pi \\frac{\\boldsymbol{r}}{r}\\times \\left\\{<br \/>\n\\begin{array}{ll}<br \/>\n{\\displaystyle \\frac{2}{r^2}} &amp; (r \\geq r&#8217;)\\\\ \\ \\\\<br \/>\n0 &amp; (r &lt; r&#8217;)<br \/>\n\\end{array}<br \/>\n\\right.\\\\<br \/>\n&amp;=&amp;\\left\\{<br \/>\n\\begin{array}{ll}<br \/>\n{\\displaystyle \\frac{4\\pi \\boldsymbol{r}}{r^3}} &amp; (r \\geq r&#8217;)\\\\ \\ \\\\<br \/>\n0 &amp; (r &lt; r&#8217;)<br \/>\n\\end{array}<br \/>\n\\right.<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3088\u3063\u3066\u3081\u3067\u305f\u304f\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\boldsymbol{E} &amp;=&amp; \\frac{1}{4\\pi\\varepsilon_0} \\int_0^{\\infty} (r&#8217;)^2 d r&#8217; \\rho(r&#8217;) \\boldsymbol{F} \\\\<br \/>\n&amp;=&amp; \\frac{1}{4\\pi\\varepsilon_0} \\int_0^{r} (r&#8217;)^2 d r&#8217;\\rho(r&#8217;)\u00a0 \\frac{4\\pi \\boldsymbol{r} }{r^3} \\\\<br \/>\n&amp;=&amp; \\frac{1}{4\\pi\\varepsilon_0} \\frac{\\boldsymbol{r} }{r^3}\\int_0^{r} 4\\pi(r&#8217;)^2 \\rho(r&#8217;)\u00a0 d r&#8217;\\\\<br \/>\n&amp;=&amp; \\frac{Q_r}{4\\pi\\varepsilon_0} \\frac{\\boldsymbol{r} }{r^3}<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3068\u306a\u308b\u3002<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u9759\u96fb\u5834\u3092\u6c42\u3081\u308b\u969b\u306b\u4f7f\u3063\u305f\u7a4d\u5206\u306f Maxima \u3092\u6570\u5b66\u516c\u5f0f\u96c6\u3068\u3057\u3066\u4f7f\u3046\u3053\u3068\u3067\u78ba\u8a8d\u3067\u304d\u3066\u3044\u308b\u304c\uff0cMaxima \u3067\u89e3\u6790\u7684\u306b\u7a4d\u5206\u3067\u304d\u308b\u3053\u3068\u304c\u308f\u304b\u308c\u3070\uff0c\u4eba\u529b\u3067\u3082\u89e3\u3044\u3066\u307f\u305f\u304f\u306a\u308b\u3082\u306e\u3002\u305d\u306e\u30b7\u30ea\u30fc\u30ba\u7b2c4\u8a71\u306f\uff0c\u7403\u5bfe\u79f0\u306a\u96fb\u8377\u5206\u5e03\u306b\u3088\u308b\u96fb\u5834\u3092\u6c42\u3081\u308b\u969b\u306b\u4f7f\u3063\u305f\u7a4d\u5206\u3002\u96fb\u78c1\u6c17\u5b66\u3068\u3044\u3046\u3088\u308a\u306f\u7406\u5de5\u7cfb\u306e\u6570\u5b66B\uff08\u5fae\u5206\u7a4d\u5206\uff09\u306e\u6f14\u7fd2\u554f\u984c\u7528\u306b\u3002<\/p><p><a class=\"more-link btn\" href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/4811\/\">\u7d9a\u304d\u3092\u8aad\u3080<\/a><\/p>\n","protected":false},"author":33,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"inline_featured_image":false,"footnotes":""},"categories":[19],"tags":[],"class_list":["post-4811","post","type-post","status-publish","format-standard","hentry","category-19","nodate","item-wrap"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts\/4811","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/users\/33"}],"replies":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/comments?post=4811"}],"version-history":[{"count":15,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts\/4811\/revisions"}],"predecessor-version":[{"id":4879,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/posts\/4811\/revisions\/4879"}],"wp:attachment":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/media?parent=4811"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/categories?post=4811"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/tags?post=4811"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}