{"id":6418,"date":"2023-06-01T15:06:13","date_gmt":"2023-06-01T06:06:13","guid":{"rendered":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/?page_id=6418"},"modified":"2024-04-17T10:36:04","modified_gmt":"2024-04-17T01:36:04","slug":"%e7%b7%b4%e7%bf%92%e5%95%8f%e9%a1%8c%e3%81%ae%e8%a7%a3%e7%ad%94%e4%be%8b","status":"publish","type":"page","link":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e7%90%86%e5%b7%a5%e7%b3%bb%e3%81%ae%e6%95%b0%e5%ad%a6b\/%e5%ba%83%e7%be%a9%e3%81%ae%e7%a9%8d%e5%88%86\/%e7%b7%b4%e7%bf%92%e5%95%8f%e9%a1%8c%e3%81%ae%e8%a7%a3%e7%ad%94%e4%be%8b\/","title":{"rendered":"\u7df4\u7fd2\u554f\u984c\u306e\u89e3\u7b54\u4f8b"},"content":{"rendered":"<p><!--more--><\/p>\n<h3>\u7df4\u7fd2\u554f\u984c 1.<\/h3>\n<p dir=\"ltr\">\\(\\displaystyle \\int_{-\\infty}^{\\infty} \\frac{1}{(a^2 + x^2)^{\\frac{3}{2}}} dx\\)<\/p>\n<p dir=\"ltr\">\u4e00\u898b\uff0c\u7121\u9650\u533a\u9593\u306e\u7a4d\u5206\u3060\u304c\uff0c\\(\\tan\\theta\\) \u3092\u542b\u3080\u5909\u6570\u5909\u63db\u306b\u3088\u308b\u7f6e\u63db\u7a4d\u5206\u306b\u3059\u308c\u3070\uff0c\\(\\displaystyle -\\frac{\\pi}{2} \\le \\theta \\le \\frac{\\pi}{2}\\) \u306e\u6709\u9650\u533a\u9593\u3067\u306e\u5b9a\u7a4d\u5206\u306b\u5e30\u7740\u3059\u308b\u5834\u5408\u3082\u3042\u308b\u3002<\/p>\n<h4 dir=\"ltr\">\u4e0d\u5b9a\u7a4d\u5206<\/h4>\n<p dir=\"ltr\">\u307e\u305a\uff0c\u4e0d\u5b9a\u7a4d\u5206\u306f\u300c\u7121\u7406\u95a2\u6570\u306e\u7a4d\u5206\u300d\u306e\u7df4\u7fd2\u554f\u984c 4. \u305d\u306e\u3082\u306e\u3002<\/p>\n<p id=\"yui_3_17_2_1_1685599369125_1177\" dir=\"ltr\">\\(x = a \\tan\\theta\\) \u3068\u304a\u3044\u3066\u7f6e\u63db\u7a4d\u5206\u3002\\(\\displaystyle dx = \\frac{a}{\\cos^2\\theta}\\, d\\theta\\) \u3067\u3042\u308b\u304b\u3089&#8230;<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int \\frac{1}{(a^2 + x^2)^{\\frac{3}{2}}} dx &amp;=&amp;<br \/>\n\\int\\frac{1}{(a^2 + a^2 \\tan^2\\theta)^{\\frac{3}{2}}}\\frac{a}{\\cos^2\\theta} d\\theta \\\\<br \/>\n&amp;=&amp;<br \/>\n\\int\\frac{1}{a^3 (1 + \\tan^2\\theta)^{\\frac{3}{2}}}\\frac{a}{\\cos^2\\theta} d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\int \\cos\\theta\\, d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\sin\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\tan\\theta \\times \\cos\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\frac{\\tan\\theta}{\\sqrt{1 + \\tan^2\\theta}} \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\frac{a \\tan\\theta}{\\sqrt{a^2 + a^2\\tan^2\\theta}} \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\frac{x}{\\sqrt{a^2 + x^2}} \\\\<br \/>\n\\end{eqnarray}<\/p>\n<h4 dir=\"ltr\">\u4e0d\u5b9a\u7a4d\u5206\u306e\u5225\u89e3<\/h4>\n<p dir=\"ltr\">\u4e00\u65e6\u7b54\u3048\u304c\u308f\u304b\u308c\u3070\uff0c\u3044\u304b\u3088\u3046\u306b\u3082\u3053\u3058\u3064\u3051\u306f\u3067\u304d\u308b\u308f\u3051\u3067\uff0c\u4ee5\u4e0b\u306e\u3088\u3046\u306a\u5225\u89e3\u3082\u53ef\u80fd\u3002<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\frac{1}{(a^2 + x^2)^{\\frac{3}{2}}} &amp;=&amp; \\frac{1}{\\sqrt{a^2 + x^2}} \\frac{1}{a^2 + x^2} \\\\<br \/>\n&amp;=&amp; \\frac{1}{\\sqrt{a^2 + x^2}} \\frac{1}{a^2} \\left( 1 -\\frac{x^2}{a^2 + x^2}\\right) \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\left( \\frac{1}{\\sqrt{a^2 + x^2}} -x \\frac{x}{(a^2 + x^2)^{\\frac{3}{2}}}\\right) \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\frac{d}{dx} \\frac{x}{\\sqrt{a^2 + x^2}} \\\\<br \/>\n\\therefore \\ \\ \\int \\frac{1}{(a^2 + x^2)^{\\frac{3}{2}}} dx &amp;=&amp; \\int \\frac{1}{a^2} \\frac{d}{dx} \\frac{x}{\\sqrt{a^2 + x^2}} dx \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\frac{x}{\\sqrt{a^2 + x^2}}<br \/>\n\\end{eqnarray}<\/p>\n<h4 dir=\"ltr\">\u5b9a\u7a4d\u5206<\/h4>\n<p dir=\"ltr\">\\(x = a \\tan\\theta\\) \u3068\u304a\u3044\u3066\u7f6e\u63db\u7a4d\u5206\u3060\u3068<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int_{-\\infty}^{\\infty} \\frac{1}{(a^2 + x^2)^{\\frac{3}{2}}} dx &amp;=&amp;<br \/>\n\\int_{-\\frac{\\pi}{2}}^{\\frac{\\pi}{2}}\\frac{1}{(a^2 + a^2 \\tan^2\\theta)^{\\frac{3}{2}}}\\frac{a}{\\cos^2\\theta} d\\theta \\\\<br \/>\n&amp;=&amp;<br \/>\n\\int_{-\\frac{\\pi}{2}}^{\\frac{\\pi}{2}}\\frac{1}{a^3 (1 + \\tan^2\\theta)^{\\frac{3}{2}}}\\frac{a}{\\cos^2\\theta} d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\int_{-\\frac{\\pi}{2}}^{\\frac{\\pi}{2}} \\cos\\theta\\, d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2} \\Bigl[\\sin\\theta\\Bigr]_{-\\frac{\\pi}{2}}^{\\frac{\\pi}{2}} \\\\<br \/>\n&amp;=&amp;\\frac{1}{a^2} \\left(1 -\\left(-1\\right)\\right) \\\\<br \/>\n&amp;=&amp; \\frac{2}{a^2}<br \/>\n\\end{eqnarray}<\/p>\n<p dir=\"ltr\">\u307e\u305f\u306f<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int_{-\\infty}^{\\infty} \\frac{1}{(a^2 + x^2)^{\\frac{3}{2}}} dx<br \/>\n&amp;=&amp; \\lim_{b\\rightarrow \\infty}\\frac{1}{a^2} \\Bigl[\\frac{x}{\\sqrt{a^2 + x^2}}\\Bigr]_{-b}^b \\\\<br \/>\n&amp;=&amp; \\lim_{b\\rightarrow \\infty}\\frac{1}{a^2} \\Bigl[\\frac{x}{\\sqrt{x^2}}\\Bigr]_{-b}^b \\\\<br \/>\n&amp;=&amp; \\frac{1}{a^2}\\lim_{b\\rightarrow \\infty}\\left( \\frac{b}{|b|} -\\frac{-b}{|b|}\\right) \\\\<br \/>\n&amp;=&amp; \\frac{2}{a^2}<br \/>\n\\end{eqnarray}<\/p>\n<h3 dir=\"ltr\">\u7df4\u7fd2\u554f\u984c 2.<\/h3>\n<p dir=\"ltr\">\\(\\displaystyle \\int_{-\\infty}^{\\infty} \\frac{1}{a^2 + x^2} dx\\)<\/p>\n<p dir=\"ltr\">\u4e00\u898b\uff0c\u7121\u9650\u533a\u9593\u306e\u7a4d\u5206\u3060\u304c\uff0c\\(\\tan\\theta\\) \u3092\u542b\u3080\u5909\u6570\u5909\u63db\u306b\u3088\u308b\u7f6e\u63db\u7a4d\u5206\u306b\u3059\u308c\u3070\uff0c\\(\\displaystyle -\\frac{\\pi}{2} \\le \\theta \\le \\frac{\\pi}{2}\\) \u306e\u6709\u9650\u533a\u9593\u3067\u306e\u5b9a\u7a4d\u5206\u306b\u5e30\u7740\u3059\u308b\u5834\u5408\u3082\u3042\u308b\u3002<\/p>\n<h4 dir=\"ltr\">\u4e0d\u5b9a\u7a4d\u5206<\/h4>\n<p dir=\"ltr\">\u307e\u305a\u306f\u4e0d\u5b9a\u7a4d\u5206\u3002<\/p>\n<p dir=\"ltr\">\\( x = a \\tan\\theta\\) \u3068\u304a\u3044\u3066\u7f6e\u63db\u7a4d\u5206<\/p>\n<p id=\"yui_3_17_2_1_1685599450232_1176\" dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int \\frac{1}{a^2 + x^2} dx &amp;=&amp; \\int \\frac{1}{a^2} \\frac{1}{1+\\tan^2 \\theta} \\frac{a}{\\cos^2\\theta} \\,d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{1}{a} \\int \\,d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{\\theta}{a} \\\\<br \/>\n&amp;=&amp;\u00a0 \\frac{\\tan^{-1}\\frac{x}{a}}{a}<br \/>\n\\end{eqnarray}<\/p>\n<p dir=\"ltr\">\u3042\u308b\u3044\u306f \\(\\displaystyle \\frac{d}{dx} \\tan^{-1} x = \\frac{1}{1+x^2}\\) \u304c\u308f\u304b\u3063\u3066\u3044\u308c\u3070\uff0c\u810a\u9ac4\u53cd\u5c04\u3067<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int \\frac{1}{a^2 + x^2} dx &amp;=&amp; \\frac{1}{a} \\int \\frac{1}{1 + \\left(\\frac{x}{a}\\right)^2} d\\left(\\frac{x}{a} \\right)\\\\<br \/>\n&amp;=&amp; \\frac{\\tan^{-1}\\frac{x}{a}}{a}<br \/>\n\\end{eqnarray}<\/p>\n<h4 dir=\"ltr\">\u5b9a\u7a4d\u5206<\/h4>\n<p>\\( x = a \\tan\\theta\\) \u3068\u304a\u3044\u3066\u7f6e\u63db\u7a4d\u5206\u3059\u308c\u3070<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int_{-\\infty}^{\\infty} \\frac{1}{a^2 + x^2} dx &amp;=&amp;<br \/>\n\\frac{1}{a} \\Bigl[\\theta\\Bigr]_{-\\frac{\\pi}{2}}^{\\frac{\\pi}{2}} \\\\<br \/>\n&amp;=&amp; \\frac{\\pi}{a}<br \/>\n\\end{eqnarray}<\/p>\n<p dir=\"ltr\">\u3053\u308c\u3067\u5b89\u5fc3\u3057\u3066\u306f\u3044\u3051\u306a\u3044\u3002\u3053\u3053\u3067\u306f \\(a &gt; 0\\) \u304c\u4eee\u5b9a\u3055\u308c\u3066\u3044\u308b\u3053\u3068\u306b\u6ce8\u610f\u3002<\/p>\n<p dir=\"ltr\">\\(a &lt; 0\\) \u306e\u3068\u304d\u306b\u306f\uff0c<br \/>\n\\begin{eqnarray}<br \/>\n\\int_{-\\infty}^{\\infty} \\frac{1}{a^2 + x^2} dx &amp;=&amp;<br \/>\n\\frac{1}{a} \\Bigl[\\theta\\Bigr]^{-\\frac{\\pi}{2}}_{\\frac{\\pi}{2}} \\\\<br \/>\n&amp;=&amp; -\\frac{\\pi}{a} \\\\<br \/>\n&amp;=&amp; \\frac{\\pi}{|a|}<br \/>\n\\end{eqnarray}<\/p>\n<p dir=\"ltr\">\u3068\u3044\u3046\u3053\u3068\u3067 \\(a &gt; 0\\) \u306e\u3068\u304d\u3082 \\(a &lt; 0\\) \u306e\u3068\u304d\u306b\u3082\u4f7f\u3048\u308b\u5f62\u3067<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int_{-\\infty}^{\\infty} \\frac{1}{a^2 + x^2} dx &amp;=&amp;<br \/>\n\\frac{\\pi}{|a|}<br \/>\n\\end{eqnarray}<\/p>\n<p dir=\"ltr\">\u307e\u3068\u3081\u308b\u3068\uff0c\u5b9a\u7a4d\u5206\u306e\u5834\u5408\u306f\uff0c\u7a4d\u5206\u7bc4\u56f2\u306e\u5909\u63db\u304c\u3042\u308b\u304b\u3089\uff0c\u6700\u521d\u304b\u3089 \\( x = |a| \\tan\\theta\\) \u3068\u304a\u3044\u3066\u7f6e\u63db\u7a4d\u5206\u3059\u308c\u3070<\/p>\n<p dir=\"ltr\">\\begin{eqnarray}<br \/>\n\\int_{-\\infty}^{\\infty} \\frac{1}{a^2 + x^2} dx &amp;=&amp;<br \/>\n\\frac{\\pi}{|a|}<br \/>\n\\end{eqnarray}<\/p>\n<p dir=\"ltr\">\n","protected":false},"excerpt":{"rendered":"","protected":false},"author":33,"featured_media":0,"parent":3274,"menu_order":2,"comment_status":"closed","ping_status":"closed","template":"","meta":{"inline_featured_image":false,"footnotes":""},"class_list":["post-6418","page","type-page","status-publish","hentry","nodate","item-wrap"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.10 - aioseo.com -->\n\t<meta name=\"description\" content=\"\u7df4\u7fd2\u554f\u984c 1. \\(\\displaystyle \\int_{-\\infty}^{\\infty} \\frac{1\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e7%90%86%e5%b7%a5%e7%b3%bb%e3%81%ae%e6%95%b0%e5%ad%a6b\/%e5%ba%83%e7%be%a9%e3%81%ae%e7%a9%8d%e5%88%86\/%e7%b7%b4%e7%bf%92%e5%95%8f%e9%a1%8c%e3%81%ae%e8%a7%a3%e7%ad%94%e4%be%8b\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 4.9.10\" \/>\n\t\t<meta property=\"og:locale\" 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