{"id":4976,"date":"2023-01-12T16:53:56","date_gmt":"2023-01-12T07:53:56","guid":{"rendered":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/?page_id=4976"},"modified":"2025-01-23T10:10:14","modified_gmt":"2025-01-23T01:10:14","slug":"%e5%8d%98%e6%8c%af%e3%82%8a%e5%ad%90%e3%81%ae%e3%82%a8%e3%83%8d%e3%83%ab%e3%82%ae%e3%83%bc%e4%bf%9d%e5%ad%98%e5%89%87%e3%81%8b%e3%82%89%e5%91%a8%e6%9c%9f%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b%e6%ba%96","status":"publish","type":"page","link":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e3%82%b3%e3%83%b3%e3%83%94%e3%83%a5%e3%83%bc%e3%82%bf%e6%bc%94%e7%bf%92\/%e5%8d%98%e6%8c%af%e3%82%8a%e5%ad%90%e3%81%ae%e3%82%a8%e3%83%8d%e3%83%ab%e3%82%ae%e3%83%bc%e4%bf%9d%e5%ad%98%e5%89%87%e3%81%8b%e3%82%89%e5%91%a8%e6%9c%9f%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b%e6%ba%96\/","title":{"rendered":"\u5358\u632f\u308a\u5b50\u306e\u30a8\u30cd\u30eb\u30ae\u30fc\u4fdd\u5b58\u5247\u304b\u3089\u5468\u671f\u3092\u6c42\u3081\u308b\u6e96\u5099"},"content":{"rendered":"<p>\u5358\u632f\u308a\u5b50\u306e\u904b\u52d5\u65b9\u7a0b\u5f0f\u304b\u3089\u5f97\u3089\u308c\u308b\u30a8\u30cd\u30eb\u30ae\u30fc\u4fdd\u5b58\u5247\u304b\u3089\uff0c\u6570\u5024\u7a4d\u5206\u306b\u3088\u3063\u3066\u5468\u671f\u3092\u6c42\u3081\u308b\u305f\u3081\u306e\u6e96\u5099\u3002<\/p>\n<p><!--more--><\/p>\n<h3>\u554f\u984c<span id=\"3\">\uff083\u629e\uff09<\/span><\/h3>\n<p>\u307e\u305a\u306f\u4e88\u60f3\u3092\u7acb\u3066\u3066\u307f\u3088\u3046\u3002<\/p>\n<p>\u5358\u632f\u308a\u5b50\u306e\u632f\u5e45\u304c\u5927\u304d\u304f\u306a\u308b\u3068\uff08\u300c\u5341\u5206\u306b\u5c0f\u3055\u3044\u300d\u3068\u3044\u3046\u8fd1\u4f3c\u304c\u6210\u308a\u7acb\u305f\u306a\u304f\u306a\u308b\u3068\uff09\uff0c\u5358\u632f\u308a\u5b50\u306e\u5468\u671f\u306f\uff0c\u5358\u632f\u52d5\u306e\u5834\u5408\u306e\u5468\u671f\u306b\u304f\u3089\u3079\u3066&#8230;<\/p>\n<ol>\n<li>\u300c\u632f\u308a\u5b50\u306e\u7b49\u6642\u6027\u300d\u304c\u3042\u308b\u304b\u3089\u5909\u5316\u3057\u306a\u3044\uff0c\u4e00\u5b9a\u306e\u307e\u307e\u3067\u3042\u308b\u3002<\/li>\n<li>\u632f\u5e45\u304c\u5927\u304d\u304f\u306a\u308c\u3070\u306a\u308b\u307b\u3069\uff0c\u5468\u671f\u306f\u9577\u304f\u306a\u308b\u3002<\/li>\n<li>\u632f\u5e45\u304c\u5927\u304d\u304f\u306a\u308c\u3070\u306a\u308b\u307b\u3069\uff0c\u5468\u671f\u306f\u77ed\u304f\u306a\u308b\u3002<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<h3>\u4fdd\u5b58\u91cf\uff08\u30a8\u30cd\u30eb\u30ae\u30fc\u4fdd\u5b58\u5247\uff09<\/h3>\n<p>\u7121\u6b21\u5143\u5316\u3055\u308c\u305f\u904b\u52d5\u65b9\u7a0b\u5f0f<\/p>\n<p>$$ \\frac{d^2\\theta}{dT^2} = -4\\pi^2 \\sin\\theta$$<\/p>\n<p>\u306e\u4e21\u8fba\u306b $\\displaystyle \\frac{d\\theta}{dT}$ \u3092\u304b\u3051\u3066\u6574\u7406\u3059\u308b\u3068\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\frac{d\\theta}{dT}\\frac{d^2\\theta}{dT^2}+4\\pi^2 \\sin\\theta\u00a0 \\frac{d\\theta}{dT}&amp;=&amp; 0 \\\\<br \/>\n\\frac{d}{dT}\\left\\{<br \/>\n\\frac{1}{2}\\left( \\frac{d\\theta}{dT} \\right)^2 -4\\pi^2 \\cos\\theta<br \/>\n\\right\\} &amp;=&amp; 0 \\\\<br \/>\n\\therefore\\ \\ \\frac{1}{2}\\left( \\frac{d\\theta}{dT} \\right)^2 -4\\pi^2 \\cos\\theta<br \/>\n&amp;=&amp; \\mbox{const.} \\equiv \\varepsilon<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3064\u307e\u308a\uff0c<\/p>\n<p>$$<br \/>\n\\varepsilon = \\frac{1}{2}\\left( \\frac{d\\theta}{dT} \\right)^2 -4\\pi^2 \\cos\\theta<br \/>\n$$<\/p>\n<p>\u3068\u3044\u3046\u4fdd\u5b58\u91cf\u304c\u5b58\u5728\u3059\u308b\u3053\u3068\u304c\u308f\u304b\u308b\u3002\u3053\u308c\u306f\u30a8\u30cd\u30eb\u30ae\u30fc\u4fdd\u5b58\u5247\u306b\u76f8\u5f53\u3059\u308b\u3002<\/p>\n<p>$T = 0$ \u3067 $\\displaystyle \\theta = \\theta_0, \\frac{d\\theta}{dT} = 0$ \u3068\u3044\u3046\u521d\u671f\u6761\u4ef6\u3092\u8ab2\u3059\u3068\uff0c\u5b9a\u6570 $\\varepsilon$ \u306e\u5024\u306f\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u5b9a\u307e\u308b\u3002<br \/>\n$$ \\varepsilon = -4\\pi^2 \\cos\\theta_0$$<\/p>\n<p>\u3064\u307e\u308a\uff0c$\\theta = \\theta_0$ \u304b\u3089 $\\theta = 0$ \u307e\u3067 $\\frac{d\\theta}{dT} &lt; 0$ \u306e\u72b6\u6cc1\u3092\u8003\u3048\u308b\u3053\u3068\u306b\u3057\u3066<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\frac{1}{2}\\left( \\frac{d\\theta}{dT} \\right)^2 &amp;=&amp; 4\\pi^2 \\left( \\cos\\theta-\\cos\\theta_0\\right)\\\\<br \/>\n\\frac{d\\theta}{dT} &amp;=&amp; -2\\pi \\sqrt{2(\\cos\\theta-\\cos\\theta_0)} \\\\<br \/>\n-\\frac{1}{2\\pi} \\frac{d\\theta}{\\sqrt{2(\\cos\\theta-\\cos\\theta_0)}} &amp;=&amp; dT<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3053\u308c\u306f\u5909\u6570\u5206\u96e2\u5f62\u306e\u5fae\u5206\u65b9\u7a0b\u5f0f\u3067\u3042\u308a\uff0c$\\theta$ \u304c $\\theta_0$ \u304b\u3089 $0$ \u307e\u3067\u306e\u6642\u9593\u306e4\u500d\u304c\u5468\u671f $T_p$ \u306b\u306a\u308b\u3053\u3068\u304b\u3089\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n-\\frac{1}{2\\pi} \\int^0_{\\theta_0} \\frac{d\\theta}{\\sqrt{2(\\cos\\theta-\\cos\\theta_0)}} &amp;=&amp; \\int_0^{\\frac{T_p}{4}} dT<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3059\u306a\u308f\u3061<\/p>\n<p>$$<br \/>\nT_p = \\frac{2}{\\pi} \\int_0^{\\theta_0} \\frac{1}{\\sqrt{2(\\cos\\theta-\\cos\\theta_0)}}d\\theta<br \/>\n$$<\/p>\n<h3>\u88ab\u7a4d\u5206\u95a2\u6570\u304c\u767a\u6563\u3059\u308b\u3068\u56f0\u308b\uff1f<\/h3>\n<p>\u3053\u306e\u7a4d\u5206\u306f\u89e3\u6790\u7684\u306b\u306f\u89e3\u3051\u306a\u3044\u306e\u3067\u6570\u5024\u7a4d\u5206\u3059\u308c\u3070\u3044\u3044\u3068\u601d\u3044\u307e\u3059\u304c\uff0c\u3053\u306e\u307e\u307e\u306e\u5f62\u3060\u3068\uff0c\u7a4d\u5206\u533a\u9593\u306e\u4e0a\u9650\u3067\u88ab\u7a4d\u5206\u95a2\u6570\u306e\u5206\u6bcd\u304c\u30bc\u30ed\u306b\u306a\u3063\u3066\u3057\u307e\u3044\uff0c\u3064\u307e\u308a\u306f\u88ab\u7a4d\u5206\u95a2\u6570\u304c\u767a\u6563\u3057\u3066\u3057\u307e\u3046\u306e\u3067\uff0c\u5927\u5909\u306a\u3053\u3068\u304c\u304a\u3053\u308a\u305d\u3046&#8230;<\/p>\n<h3>Maxima \u306e <code>quad_qags()<\/code> \u3084 Python \u306e <code>scipy.integrate.quad()<\/code> \u306a\u3089\u7121\u554f\u984c<\/h3>\n<p>&#8230; \u306a\u3069\u3068\uff0c\u3044\u308d\u3044\u308d\u5fc3\u914d\u3057\u307e\u3057\u305f\u304c\uff0c\u88ab\u7a4d\u5206\u95a2\u6570\u304c\u767a\u6563\u3059\u308b\u304b\u3089\u3068\u3044\u3063\u3066\u7a4d\u5206\u305d\u306e\u3082\u306e\u304c\u767a\u6563\u3059\u308b\u308f\u3051\u3067\u306f\u3042\u308a\u307e\u305b\u3093\u3002\u6570\u5024\u7a4d\u5206\u3092\u3059\u308b\u95a2\u6570\u3067\u3042\u308b Maxima \u306e <code>quad_qags()<\/code> \uff08<code>romberg()<\/code> \u306f\u30c0\u30e1\uff09\u3084\uff0cPython \u306e <code>scipy.integrate.quad()<\/code> \u306f\uff0c$\\theta = \\theta_0$ \u3067\u88ab\u7a4d\u5206\u95a2\u6570\u304c\u767a\u6563\u3057\u3066\u3057\u307e\u3046\u3088\u3046\u306a\u5834\u5408\u3067\u3082\uff0c\u4f55\u4e8b\u3082\u306a\u304b\u3063\u305f\u3088\u3046\u306b\u6570\u5024\u7a4d\u5206\u3057\u3066\u3057\u307e\u3044\u307e\u3059\u3002<\/p>\n<h3>\u7b2c1\u7a2e\u5b8c\u5168\u6955\u5186\u7a4d\u5206<\/h3>\n<p>\u3053\u3053\u3067\u306f\uff0c\u4e0a\u8a18\u306e\u7a4d\u5206\u304c\u5909\u6570\u5909\u63db\u306b\u3088\u3063\u3066\uff0c<span style=\"font-family: helvetica, arial, sans-serif;\"><strong>\u7b2c1\u7a2e\u5b8c\u5168\u6955\u5186\u7a4d\u5206<\/strong><\/span> $K(k)$ \u3092\u4f7f\u3063\u3066<br \/>\n\\begin{eqnarray}<br \/>\n\\int_0^{\\theta_0} \\frac{1}{\\sqrt{2(\\cos\\theta-\\cos\\theta_0)}} d\\theta<br \/>\n&amp;=&amp; K(k) \\\\&amp;\\equiv&amp;<br \/>\n\\int_0^{\\pi\/2} \\frac{dt}{\\sqrt{1 -k^2 \\sin^2 t}}, \\quad k = \\sin\\frac{\\theta_0}{2}<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3067\u66f8\u3051\u308b\u3053\u3068\u3092\u793a\u3059\u3002\u3053\u306e\u5f62\u3060\u3068\uff0c$k^2 &lt; 1$ \u306a\u3089\u7a4d\u5206\u533a\u9593\u5185\u3067\u88ab\u7a4d\u5206\u95a2\u6570\u304c\u767a\u6563\u3059\u308b\u3053\u3068\u3082\u306a\u304f\uff0c\u6570\u5024\u7a4d\u5206\u306b\u56f0\u308b\u3053\u3068\u3082\u306a\u3044\u3002<\/p>\n<p>\u307e\u305a\uff0c\u5206\u6bcd\u306f\u534a\u89d2\u306e\u516c\u5f0f\u3092\u4f7f\u3063\u3066<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\sqrt{2 (\\cos\\theta-\\cos\\theta_0)} &amp;=&amp;<br \/>\n\\sqrt{2 \\left\\{ \\left(1-2\\sin^2\\frac{\\theta}{2}\\right)<br \/>\n-\\left(1-2\\sin^2\\frac{\\theta_0}{2}\\right)<br \/>\n\\right\\} }\\\\<br \/>\n&amp;=&amp; 2\\sqrt{\\sin^2\\frac{\\theta_0}{2} -\\sin^2\\frac{\\theta}{2}}<br \/>\n\\end{eqnarray}<\/p>\n<p>\u3053\u3053\u3067\uff0c<\/p>\n<p>$$\\displaystyle \\sin\\frac{\\theta_0}{2} \\equiv k, \\quad<br \/>\n\\sin\\frac{\\theta}{2} \\equiv k \\sin t<br \/>\n$$<\/p>\n<p>\u3068\u304a\u304f\u3068\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n2\\sqrt{\\sin^2\\frac{\\theta_0}{2} -\\sin^2\\frac{\\theta}{2}}<br \/>\n&amp;=&amp; 2 k \\sqrt{1 -\\sin^2 t} \\\\<br \/>\n&amp;=&amp; 2 k \\cos t<br \/>\n\\end{eqnarray}<\/p>\n<p>\u4e00\u65b9\uff0c\u5206\u5b50\u306f<\/p>\n<p>$$ \\sin\\frac{\\theta}{2} \\equiv k \\sin t $$<\/p>\n<p>\u306e\u5fae\u5206\u3092\u3068\u308b\u3053\u3068\u306b\u3088\u308a\uff0c<\/p>\n<p>$$ \\cos\\frac{\\theta}{2} \\frac{d\\theta}{2} = k \\cos t \\, dt$$<\/p>\n<p>$$<br \/>\n\\therefore \\ d\\theta = \\frac{2 k \\cos t}{\\cos\\frac{\\theta}{2}} dt<br \/>\n= \\frac{2 k \\cos t}{\\sqrt{1-\\sin^2\\frac{\\theta}{2}}} dt<br \/>\n= \\frac{2 k \\cos t}{\\sqrt{1-k^2 \\sin^2 t}} dt<br \/>\n$$<\/p>\n<p>\u3057\u305f\u304c\u3063\u3066\uff0c<\/p>\n<p>\\begin{eqnarray}<br \/>\n\\int_0^{\\theta_0} \\frac{1}{\\sqrt{2(\\cos\\theta-\\cos\\theta_0)}} d\\theta<br \/>\n&amp;=&amp;\\int_0^{\\pi\/2}<br \/>\n\\frac{1}{2 k \\cos t} \\frac{2 k \\cos t}{\\sqrt{1-k^2 \\sin^2 t}} dt\\\\<br \/>\n&amp;=&amp;\\int_0^{\\pi\/2} \\frac{dt}{\\sqrt{1-k^2 \\sin^2 t}}\\\\<br \/>\n&amp;\\equiv&amp; K(k)<br \/>\n\\end{eqnarray}<\/p>\n<p><span style=\"font-family: helvetica, arial, sans-serif;\"><strong>\u7b2c1\u7a2e\u5b8c\u5168\u6955\u5186\u7a4d\u5206<\/strong><\/span> $K(k)$ \u3092\u4f7f\u3046\u3068\uff0c\u632f\u5e45 $\\theta_0$ \u306e\u5358\u632f\u308a\u5b50\u306e\u5468\u671f $T_p$ \u306f<\/p>\n<p>\\begin{eqnarray}<br \/>\nT_p(\\theta_0) &amp;=&amp;<br \/>\n\\frac{2}{\\pi} \\int_{0}^{\\theta_0} \\frac{1}{\\sqrt{2(\\cos\\theta-\\cos\\theta_0)}}d\\theta \\\\<br \/>\n&amp;=&amp; \\frac{2}{\\pi} K(k) \\\\<br \/>\n&amp;=&amp; \\frac{2}{\\pi}\\int_0^{\\pi\/2} \\frac{dt}{\\sqrt{1-k^2 \\sin^2 t}}, \\quad k \\equiv \\sin\\frac{\\theta_0}{2}<br \/>\n\\end{eqnarray}<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u5358\u632f\u308a\u5b50\u306e\u904b\u52d5\u65b9\u7a0b\u5f0f\u304b\u3089\u5f97\u3089\u308c\u308b\u30a8\u30cd\u30eb\u30ae\u30fc\u4fdd\u5b58\u5247\u304b\u3089\uff0c\u6570\u5024\u7a4d\u5206\u306b\u3088\u3063\u3066\u5468\u671f\u3092\u6c42\u3081\u308b\u305f\u3081\u306e\u6e96\u5099\u3002<\/p><p><a class=\"more-link btn\" href=\"https:\/\/home.hirosaki-u.ac.jp\/relativity\/%e3%82%b3%e3%83%b3%e3%83%94%e3%83%a5%e3%83%bc%e3%82%bf%e6%bc%94%e7%bf%92\/%e5%8d%98%e6%8c%af%e3%82%8a%e5%ad%90%e3%81%ae%e3%82%a8%e3%83%8d%e3%83%ab%e3%82%ae%e3%83%bc%e4%bf%9d%e5%ad%98%e5%89%87%e3%81%8b%e3%82%89%e5%91%a8%e6%9c%9f%e3%82%92%e6%b1%82%e3%82%81%e3%82%8b%e6%ba%96\/\">\u7d9a\u304d\u3092\u8aad\u3080<\/a><\/p>\n","protected":false},"author":33,"featured_media":0,"parent":2826,"menu_order":40,"comment_status":"closed","ping_status":"closed","template":"","meta":{"inline_featured_image":false,"footnotes":""},"class_list":["post-4976","page","type-page","status-publish","hentry","nodate","item-wrap"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/pages\/4976","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/users\/33"}],"replies":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/comments?post=4976"}],"version-history":[{"count":13,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/pages\/4976\/revisions"}],"predecessor-version":[{"id":10065,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/pages\/4976\/revisions\/10065"}],"up":[{"embeddable":true,"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/pages\/2826"}],"wp:attachment":[{"href":"https:\/\/home.hirosaki-u.ac.jp\/relativity\/wp-json\/wp\/v2\/media?parent=4976"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}